HEAT TRANSFER AND COMPARATIVE HEAT CAPACITIES
Knight Foundation Summer Institute
Terry Newirth, Haverford College
Introduction:
This is similar to the first two experiments in this section, but here the heat content of two common metals used for cooking utensils, aluminum and copper, are compared to the heat content of water. Again we measure the heat transferred from hot material to room temperature water to provide the data. The data analysis can be done very simply to provide the relative heat content, or with a slightly more sophisticated data analysis, fairly good numbers for the actual heat capacities of the metals can be determined.
There are many ways that this has direct relevance to Technology and Metals Aluminum and copper are both common metals used in the pots and pans we use to cook. We see that the heat capacity of copper is very low. That means that relatively little heat is needed to raise the temperature of copper, i.e. it heats up very fast. That is why some pots have copper bottoms, it helps to heat the pot up more quickly and evenly. Aluminum pans heat up a little more slowly, but retain more heat. Water heats up much more slowly than either metal, but retains much more heat.
Modern technology uses the large amount of heat that can be transferred from water as a source of energy, e.g. in heat pumps. Geothermal energy also relies on heat transfer. In that case air or water on the earth's surface exchanges heat with cold deep ocean waters of cool deep earth. (http://www.ghpc.org) This site shows how heat pumps work and lists some schools that use heat pumps for energy.
Objectives:
Vocabulary:
Heat Capacity
Heat Transfer
Heat Lost
Heat Gained
Materials:
Procedure:
a. Simple Method
One can get determine the relative heat content of copper, aluminum and water, by simply comparing the temperature rise of the 50 ml of water in the Styrofoam cup/g of material added. For water assume a density of 1 g/ml, so ml's = 8's. The greater the temperature rise of the water/g of sample, the greater the heat content of sample, i.e. it had more heat to transfer to the water to heat it.
b. More Advanced Method
This method involves more calculations and can be used to demonstrate, or reinforce the method of dimensional analysis. It is based on one of the most fundamental principles of science: the conservation of energy. In this context that means that all the heat that left the hot object was transferred to the cold water or
heat lost = heat gained
The heat capacity of pure water is 1 cal/g ¡C, which means that it takes one cal of heat to raise the temperature of one gram of water one degree Centigrade. For this experiment, even though we are using tap water, we will assume that our water also has a heat capacity of 1 cal/g ¡C, and a density of 1 g/ml. Since we know we started with 50 ml of water and we know how many degree the temperature of this water was raised, we can calculate how much heat, in cal, was transferred to the water. E.g. Let's say that when we put 5.4 grams of 100¡C aluminum in our water (aluminum that had been suspended in boiling water) the temperature of the 50 ml of water was raised from 26.0¡C to 27.8¡C. Since the density of water is 1 g/ml, 50 ml of water has a mass of 50 g. Therefore our calculation of the heat transferred to the water would be:
1cal/g/oC x 50g water x 1.8oC = 90cal = heat gained by water = heat lost by aluminum
Notice in dimensional analysis, units in the fractions get canceled, just like numbers do in fractions. Here we had gram in the numerator and denominator, as well as ¡C in the numerator and denominator, so they both cancel and the units of the answer are only in cal. In science calculations units are VERY important. All numbers should have units after them.
Now we know how much heat was transferred to the water. The heat obviously came from the hot material we added to the water. Heat capacity is the heat lost (or gained) per g material per ¡C. Since we know the grams of the metal we added, the change in temperature of the metal we added (100¡C final temperature of the water in the cup) and the heat transferred from that material we can calculate the heat capacity of the metal. For the example above we just plug the numbers we know into the definition of heat capacity. We had 5.4 g of Aluminum, which transferred 90 cal of heat (calculation above) and the aluminum cooled from 100¡C to 27.8¡C, or 72.2¡C. Therefore the heat capacity of aluminum is
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We have made some assumptions that aren't entirely correct, e.g. we used tap water and not pure water. We also did not use a very accurate thermometer to measure the temperature change or the volumes of water. We also assumed that no heat was transferred to the Styrofoam cup or to the air in the transfer process. Nonetheless the answers one gets from these calculations are good enough to see that the heat capacity of copper<aluminum<<<water.
Assessments:
Extensions:
Below are a list of topics that could be used in discussion with the entire class.
Philadelphia Science Content Standards:
SCIENCE CONTENT STANDARD # 1: NATURE OF SCIENCE
This content allows the students to "design, modify and conduct an investigation through testing, revising, and occasionally discarding idea, all of which lead to a better understanding of how things work." Also, as benchmark number 2 states, the students will learn to "collect and summarize data from an experiment and interpret results in terms of the data."
Cross References:
The students are using analytic skills as well as mathematical skills in the computation of their results. In the extensions, the students are using Language Arts skills to write about the topics provided.